Optimal. Leaf size=376 \[ -\frac {(i a-b)^{5/2} (A+i B) \text {ArcTan}\left (\frac {\sqrt {i a-b} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}}{d}+\frac {\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}}{8 \sqrt {b} d}+\frac {(i a+b)^{5/2} (A-i B) \tanh ^{-1}\left (\frac {\sqrt {i a+b} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}}{d}+\frac {\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt {a+b \tan (c+d x)}}{8 d \sqrt {\cot (c+d x)}}+\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}} \]
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Rubi [A]
time = 2.21, antiderivative size = 376, normalized size of antiderivative = 1.00, number of steps
used = 16, number of rules used = 11, integrand size = 35, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.314, Rules used = {4326, 3688,
3728, 3736, 6857, 65, 223, 212, 95, 211, 214} \begin {gather*} \frac {\left (5 a^2 B+14 a A b-8 b^2 B\right ) \sqrt {a+b \tan (c+d x)}}{8 d \sqrt {\cot (c+d x)}}+\frac {\left (5 a^3 B+30 a^2 A b-40 a b^2 B-16 A b^3\right ) \sqrt {\tan (c+d x)} \sqrt {\cot (c+d x)} \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right )}{8 \sqrt {b} d}-\frac {(-b+i a)^{5/2} (A+i B) \sqrt {\tan (c+d x)} \sqrt {\cot (c+d x)} \text {ArcTan}\left (\frac {\sqrt {-b+i a} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right )}{d}+\frac {(3 a B+2 A b) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}}+\frac {(b+i a)^{5/2} (A-i B) \sqrt {\tan (c+d x)} \sqrt {\cot (c+d x)} \tanh ^{-1}\left (\frac {\sqrt {b+i a} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right )}{d}+\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)} \end {gather*}
Antiderivative was successfully verified.
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Rule 65
Rule 95
Rule 211
Rule 212
Rule 214
Rule 223
Rule 3688
Rule 3728
Rule 3736
Rule 4326
Rule 6857
Rubi steps
\begin {align*} \int \frac {(a+b \tan (c+d x))^{5/2} (A+B \tan (c+d x))}{\sqrt {\cot (c+d x)}} \, dx &=\left (\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \int \sqrt {\tan (c+d x)} (a+b \tan (c+d x))^{5/2} (A+B \tan (c+d x)) \, dx\\ &=\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {1}{3} \left (\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \int \sqrt {\tan (c+d x)} \sqrt {a+b \tan (c+d x)} \left (\frac {3}{2} a (2 a A-b B)+3 \left (2 a A b+a^2 B-b^2 B\right ) \tan (c+d x)+\frac {3}{2} b (2 A b+3 a B) \tan ^2(c+d x)\right ) \, dx\\ &=\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}}+\frac {\left (\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \int \frac {\sqrt {a+b \tan (c+d x)} \left (-\frac {3}{4} a b (2 A b+3 a B)+6 b \left (a^2 A-A b^2-2 a b B\right ) \tan (c+d x)+\frac {3}{4} b \left (14 a A b+5 a^2 B-8 b^2 B\right ) \tan ^2(c+d x)\right )}{\sqrt {\tan (c+d x)}} \, dx}{6 b}\\ &=\frac {\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt {a+b \tan (c+d x)}}{8 d \sqrt {\cot (c+d x)}}+\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}}+\frac {\left (\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \int \frac {-\frac {3}{8} a b \left (18 a A b+11 a^2 B-8 b^2 B\right )+6 b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right ) \tan (c+d x)+\frac {3}{8} b \left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \tan ^2(c+d x)}{\sqrt {\tan (c+d x)} \sqrt {a+b \tan (c+d x)}} \, dx}{6 b}\\ &=\frac {\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt {a+b \tan (c+d x)}}{8 d \sqrt {\cot (c+d x)}}+\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}}+\frac {\left (\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {-\frac {3}{8} a b \left (18 a A b+11 a^2 B-8 b^2 B\right )+6 b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right ) x+\frac {3}{8} b \left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) x^2}{\sqrt {x} \sqrt {a+b x} \left (1+x^2\right )} \, dx,x,\tan (c+d x)\right )}{6 b d}\\ &=\frac {\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt {a+b \tan (c+d x)}}{8 d \sqrt {\cot (c+d x)}}+\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}}+\frac {\left (\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \left (\frac {3 b \left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right )}{8 \sqrt {x} \sqrt {a+b x}}-\frac {6 \left (b \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right )-b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right ) x\right )}{\sqrt {x} \sqrt {a+b x} \left (1+x^2\right )}\right ) \, dx,x,\tan (c+d x)\right )}{6 b d}\\ &=\frac {\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt {a+b \tan (c+d x)}}{8 d \sqrt {\cot (c+d x)}}+\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}}-\frac {\left (\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {b \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right )-b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right ) x}{\sqrt {x} \sqrt {a+b x} \left (1+x^2\right )} \, dx,x,\tan (c+d x)\right )}{b d}+\frac {\left (\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {x} \sqrt {a+b x}} \, dx,x,\tan (c+d x)\right )}{16 d}\\ &=\frac {\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt {a+b \tan (c+d x)}}{8 d \sqrt {\cot (c+d x)}}+\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}}-\frac {\left (\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \left (\frac {i b \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right )+b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right )}{2 (i-x) \sqrt {x} \sqrt {a+b x}}+\frac {i b \left (3 a^2 A b-A b^3+a^3 B-3 a b^2 B\right )-b \left (a^3 A-3 a A b^2-3 a^2 b B+b^3 B\right )}{2 \sqrt {x} (i+x) \sqrt {a+b x}}\right ) \, dx,x,\tan (c+d x)\right )}{b d}+\frac {\left (\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+b x^2}} \, dx,x,\sqrt {\tan (c+d x)}\right )}{8 d}\\ &=\frac {\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt {a+b \tan (c+d x)}}{8 d \sqrt {\cot (c+d x)}}+\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}}+\frac {\left ((a-i b)^3 (A-i B) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {x} (i+x) \sqrt {a+b x}} \, dx,x,\tan (c+d x)\right )}{2 d}-\frac {\left ((a+i b)^3 (A+i B) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{(i-x) \sqrt {x} \sqrt {a+b x}} \, dx,x,\tan (c+d x)\right )}{2 d}+\frac {\left (\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{1-b x^2} \, dx,x,\frac {\sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right )}{8 d}\\ &=\frac {\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}}{8 \sqrt {b} d}+\frac {\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt {a+b \tan (c+d x)}}{8 d \sqrt {\cot (c+d x)}}+\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}}+\frac {\left ((a-i b)^3 (A-i B) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{i-(-a+i b) x^2} \, dx,x,\frac {\sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right )}{d}-\frac {\left ((a+i b)^3 (A+i B) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}\right ) \text {Subst}\left (\int \frac {1}{i-(a+i b) x^2} \, dx,x,\frac {\sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right )}{d}\\ &=-\frac {(i a-b)^{5/2} (A+i B) \tan ^{-1}\left (\frac {\sqrt {i a-b} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}}{d}+\frac {\left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \tanh ^{-1}\left (\frac {\sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}}{8 \sqrt {b} d}+\frac {(i a+b)^{5/2} (A-i B) \tanh ^{-1}\left (\frac {\sqrt {i a+b} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right ) \sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)}}{d}+\frac {\left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt {a+b \tan (c+d x)}}{8 d \sqrt {\cot (c+d x)}}+\frac {b B (a+b \tan (c+d x))^{3/2}}{3 d \cot ^{\frac {3}{2}}(c+d x)}+\frac {(2 A b+3 a B) (a+b \tan (c+d x))^{3/2}}{4 d \sqrt {\cot (c+d x)}}\\ \end {align*}
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Mathematica [A]
time = 3.90, size = 365, normalized size = 0.97 \begin {gather*} \frac {\sqrt {\cot (c+d x)} \sqrt {\tan (c+d x)} \left (24 \sqrt [4]{-1} (-a+i b)^{5/2} (A-i B) \text {ArcTan}\left (\frac {\sqrt [4]{-1} \sqrt {-a+i b} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right )+24 \sqrt [4]{-1} (a+i b)^{5/2} (A+i B) \text {ArcTan}\left (\frac {\sqrt [4]{-1} \sqrt {a+i b} \sqrt {\tan (c+d x)}}{\sqrt {a+b \tan (c+d x)}}\right )+3 \left (14 a A b+5 a^2 B-8 b^2 B\right ) \sqrt {\tan (c+d x)} \sqrt {a+b \tan (c+d x)}+6 (2 A b+3 a B) \sqrt {\tan (c+d x)} (a+b \tan (c+d x))^{3/2}+8 b B \tan ^{\frac {3}{2}}(c+d x) (a+b \tan (c+d x))^{3/2}+\frac {3 \sqrt {a} \left (30 a^2 A b-16 A b^3+5 a^3 B-40 a b^2 B\right ) \sinh ^{-1}\left (\frac {\sqrt {b} \sqrt {\tan (c+d x)}}{\sqrt {a}}\right ) \sqrt {1+\frac {b \tan (c+d x)}{a}}}{\sqrt {b} \sqrt {a+b \tan (c+d x)}}\right )}{24 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [C] Result contains higher order function than in optimal. Order 4 vs. order
3.
time = 30.42, size = 36039, normalized size = 95.85
method | result | size |
default | \(\text {Expression too large to display}\) | \(36039\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \frac {\left (A+B\,\mathrm {tan}\left (c+d\,x\right )\right )\,{\left (a+b\,\mathrm {tan}\left (c+d\,x\right )\right )}^{5/2}}{\sqrt {\mathrm {cot}\left (c+d\,x\right )}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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